Answer:
The line charge density is [tex]1.59\times10^{-4}\ C/m[/tex]
Explanation:
Given that,
Diameter = 2.54 cm
Distance = 19.6 m
Potential difference = 115 kV
We need to calculate the line charge density
Using formula of potential difference
[tex]V=EA[/tex]
[tex]V=\dfrac{\lambda}{2\pi\epsilon_{0}r}\times\pi r^2[/tex]
[tex]\lambda=\dfrac{V\times2\epsilon_{0}}{r}[/tex]
Where, r = radius
V = potential difference
Put the value into the formula
[tex]\lambda=\dfrac{115\times10^{3}\times2\times8.8\times10^{-12}}{1.27\times10^{-2}}[/tex]
[tex]\lambda=1.59\times10^{-4}\ C/m[/tex]
Hence, The line charge density is [tex]1.59\times10^{-4}\ C/m[/tex]
