Answer:
[tex]F_{xtotal} = F_{x} - \mu N[/tex]
Explanation:
Let the total force be F
The force that produces motion in the x direction is given as, [tex]F_{x}[/tex]
Let the frictional force be given as:
[tex]F_{fric} = \mu N[/tex]
Thus, the net force is given as:
[tex]F_{xnet} = F_{x} - \mu N[/tex]