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Determine the concentration of the following dye standard made by a student who pipettes out 2.50 mL of a 0.250 M stock solution and transfers it into a volumetric flask and dilutes the dye to a final volume of 100.0 mL with DI water.

Respuesta :

Answer:

Concentration of dye in diluted solution is 0.00625 M

Explanation:

The given problem can be solved by using laws of dilution

According to laws of dilution-   [tex]C_{1}V_{1}=C_{2}V_{2}[/tex]

where [tex]C_{1}[/tex] and [tex]C_{2}[/tex] are initial and final concentration respectively

          [tex]V_{1}[/tex] and [tex]V_{2}[/tex] are initial and final volume respectively

Here, [tex]C_{1}=0.250 M[/tex], [tex]V_{1}=2.50mL[/tex] and [tex]V_{2}=100.0mL[/tex]

So, [tex]C_{2}=\frac{C_{1}V_{1}}{V_{2}}[/tex]

or, [tex]C_{2}=\frac{(0.250M)\times (2.50mL)}{100.0mL}[/tex]

or, [tex]C_{2}=0.00625M[/tex]

So, concentration of dye in diluted solution is 0.00625 M

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