Answer:
Step-by-step explanation:
Given that the weights of bags filled by a machine are normally distributed with a standard deviation of 0.055 kilograms and a mean that can be set by the operator.
Let the mean be M.
Only 1% of the bags weigh less than 10.5 kilograms
i.e. P(X<10.5) = 0.01
corresponding Z value for P(Z<z) = 0.01 is -0.025
i.e. 10.5 = M-0.025(0.055)
Solve for M from the above equation
M = [tex]10.5+0.025(0.055)\\=10.501375[/tex]
Rounding off we get
10.50 kgs
Mean weight should be fixed as 10.50 kg.