Respuesta :
Answer:
Mass of [tex]CO_{2}[/tex] gas in container = 22.56 g
Explanation:
Molar mass of [tex]O_{2}[/tex] = 32 g/mol
So, 32.8 g of [tex]O_{2}[/tex] = [tex]\frac{32.8}{32}[/tex] moles of [tex]O_{2}[/tex] = 1.025 moles of [tex]O_{2}[/tex]
Let's assume both [tex]O_{2}[/tex] and [tex]CO_{2}[/tex] inside container behaves ideally
So, for both of them, PV = nRT
Where, P is pressure, V is volume of container, n is number of moles, R is gas constant and T is temperature in kelvin scale
So, [tex]\frac{P}{RT}=\frac{n}{V}[/tex]
As P, R and T are constant for both [tex]O_{2}[/tex] and [tex]CO_{2}[/tex] therefore [tex]\frac{n}{V}[/tex] ratio for both [tex]O_{2}[/tex] and [tex]CO_{2}[/tex] will also remain constant
As [tex]O_{2}[/tex] gas container has twice the volume of [tex]CO_{2}[/tex] gas container therefore number of moles of [tex]O_{2}[/tex] gas inside container will be twice the number of moles of [tex]CO_{2}[/tex] gas inside container
Number of moles of [tex]O_{2}[/tex] gas present inside container = 1.025 moles
So, Number of moles of [tex]CO_{2}[/tex] gas present inside container = [tex]\frac{1.025}{2}[/tex] moles = 0.5125 moles
Molar mass of [tex]CO_{2}[/tex] = 44.01 g/mol
So, mass of [tex]CO_{2}[/tex] gas inside container = [tex](0.5125\times 44.01)[/tex] g = 22.56 g
