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PLEASE HELP ON THIS MATH PROBLEM
The graph of a sine function has an amplitude of 10, a midline of y = 4, and a period of 2.

There is no phase shift. The graph is reflected over the x-axis.

What is the equation of the function?

Respuesta :

tramserran

Answer:   y = -10 sin (πx) + 4

Step-by-step explanation:

y = A sin (Bx - C) + D

  • Amplitude: A
  • Period = 2π/B    --->    B = 2π/Period
  • Phase Shift = C/B  --> C = B · Phase Shift
  • D: midline, vertical shift

Given:

  • A = 10
  • B = 2π/2 = π
  • C = B · 0 = 0
  • D = 4
  • reflection over x- axis

Equation:

    y = -10 sin (πx - 0) + 4

The equation of the function should be  y = -10 sin (πx) + 4.

Calculation of the equation:

Since

y = A sin (Bx - C) + D

Here

Amplitude: A

Period = 2π/B    --->    B = 2π/Period

Phase Shift = C/B  --> C = B · Phase Shift

D: midline, vertical shift

Also, it is mentioned that

A = 10

B = 2π/2 = π

C = B · 0 = 0

D = 4

reflection over x- axis

So, here the equation is y = -10 sin (πx - 0) + 4

Learn more about equation here: https://brainly.com/question/24271130