Answer:
The answer to your question is V2 = 1244 L
Explanation:
Data
Temperature 1 = 11°C
Volume = 1.03 x 10³ L
Temperature 2 = 70°C
Volume 2 = ?
To solve this problem use the Charles' law
V1/ T1 = V2 / T2
-Solve for V2
V2 = V1T2 / T1
Process
1.- Convert temperature to °K
Temperature 1 = 11°C + 273 = 284°K
Temperature 2 = 70°C + 273 = 343°K
2.- Substitution
V2 = (1.03 x 10³)(343) / 284
3.- Simplification
V2 = 353290 / 284
4.- Result
V2 = 1244 L
Answer:
The new volume of the gas is 1244 L
Explanation:
Step 1: Data given
The initial temperature in the balloon = 11.0 °C = 284 K
The initial volume in the balloon is 1.03 *10³ L = 1030 L
The temperature increases to 70.0 °C = 343 K
The pressure stays constant
Step 2: Calculate the new volume of the gas
V1/T1 = V2/T2
⇒with V1 = the initial volume of the gas = 1030 L
⇒with T1 = the initial temperature in the balloon = 284 K
⇒with V2 = the new volume of the gas = TO BE DETERMINED
⇒with T2 = the new temperature in the balloon = 343 K
1030 L / 284 K = V2 / 343 K
V2 = 1244 L
The new volume of the gas is 1244 L
