Respuesta :
Answer:
The spring constant of this spring is 200 N/m.
Explanation:
Given:
Original unstretched length of the spring (x₀) = 10 cm =0.10 m [1 cm =0.01 m]
Stretched length of the spring (x₁) = 18 cm = 0.18 cm
Force acting on the spring (F) = 16 N
Spring constant of the spring (k) = ?
First let us find the change in length of the spring or the elongation caused in the spring due to the applied force.
So, Change in length = Final length - Initial length
[tex]\Delta x = x_1-x_0=0.18-0.10=0.08\ m[/tex]
Now, restoring force acting on the spring is directly related to its elongation or compression as:
[tex]F=k\Delta x[/tex]
Rewriting in terms of 'k', we get:
[tex]k=\dfrac{F}{\Delta x}[/tex]
Now, plug in the given values and solve for 'k'. This gives,
[tex]k=\frac{16\ N}{0.08\ m}\\\\k=200\ N/m[/tex]
Therefore, the spring constant of this spring is 200 N/m.
