Respuesta :

Answer:

0.1061 mol of Glucose

Explanation:

Glucose has moleculer formula = [tex]C_{6} H_{12} O_{6}[/tex]

Atomic Weight of Glucose([tex]C_{6} H_{12}O_{6}[/tex] ) = ( 12 × 6) + ( 1 × 12) + ( 16 × 6)                            = 180 gm/mol

180gm of Glucose = 1 mol Glucose

19.1 gm of Glucose = 19.1÷180 = 0.1061 mol of Glucose