Answer:
0.1061 mol of Glucose
Explanation:
Glucose has moleculer formula = [tex]C_{6} H_{12} O_{6}[/tex]
Atomic Weight of Glucose([tex]C_{6} H_{12}O_{6}[/tex] ) = ( 12 × 6) + ( 1 × 12) + ( 16 × 6) = 180 gm/mol
180gm of Glucose = 1 mol Glucose
19.1 gm of Glucose = 19.1÷180 = 0.1061 mol of Glucose