Respuesta :
Answer:
The empirical formula of the solid metal oxide is : [tex]MO[/tex]
Explanation:
M atom is present in the every corner and in the center of every face.
Number of m atoms :
[tex]\frac{1}{8}\times 8+\frac{1}{2}\times 6=4[/tex]
Number of tetrahedral voids in F.C.C = 2n = 2 × 4 = 8
Oxide ion is present in the half of the tetrahedral void
Number oxide ions = [tex]\frac{8}{2}=4[/tex]
The molecular formula of the solid metal oxide is : [tex]M_4O_4=MO[/tex]
The empirical formula represent the lowest number of atoms present in a compound.
The empirical formula of the solid metal oxide is : [tex]MO[/tex]
The empirical formula of this metal oxide is MO.
Calculation of the empirical formula:
Since m atom should be presented in every corner and should be centered for every face.
So here the no of atoms should be
= 1/8 *8 + 1/2 * 6
= 4
Now
Number of tetrahedral voids in F.C.C = 2n = 2 × 4 = 8
And,
Oxide ion should be present in the half of the tetrahedral void
So, the number of oxide ions should be
= 8/2
= 4
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