Respuesta :
Answer: The initial pH of the HCl solution is 3
Explanation:
To calculate the concentration of acid, we use the equation given by neutralization reaction:
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is HCl
[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is NaOH.
We are given:
[tex]n_1=1\\M_1=?M\\V_1=100mL\\n_2=1\\M_2=0.10M\\V_2=1mL[/tex]
Putting values in above equation, we get:
[tex]1\times M_1\times 100=1\times 0.10\times 1\\\\M_1=\frac{1\times 0.10\times 1}{1\times 100}=10M[/tex]
1 mole of HCl produces 1 mole of [tex]H^+[/tex] ions and 1 mole of [tex]Cl^-[/tex] ions
To calculate the pH of the solution, we use the equation:
[tex]pH=-\log[H^+][/tex]
We are given:
[tex][H^+]=0.001M[/tex]
Putting values in above equation, we get:
[tex]pH=-\log (0.001)\\\\pH=3[/tex]
Hence, the initial pH of the HCl solution is 3
