An aqueous potassium iodate ( KIO3 ) solution is made by dissolving 562 562 grams of KIO 3 KIO3 in sufficient water so that the final volume of the solution is 4.30 L. Calculate the molarity of the KIO 3 KIO3 solution.

Respuesta :

Answer:

Molarity of [tex]KIO_{3}[/tex] solution is 0.612 mol/L

Explanation:

Number of moles of a substance = (mass of substance)/(molar mass of the substance)

Molar mass of [tex]KIO_{3}[/tex] = 214 g/mol

So, 562 g of [tex]KIO_{3}[/tex] = [tex]\frac{562}{214}[/tex] moles of [tex]KIO_{3}[/tex] = 2.63 moles of [tex]KIO_{3}[/tex]

Molarity of a solution = (number of moles of solute in solution)/(total volume of solution in liter)

Here solute is [tex]KIO_{3}[/tex] and solvent is water

Total volume of solution is 4.30 L

So, molarity of [tex]KIO_{3}[/tex] solution = [tex]\frac{2.63}{4.30}mol/L[/tex] = 0.612 mol/L

The molarity of the KIO₃ solution is 0.611 M

From the question,

We are to determine the molarity of the KIO₃ solution

First, we will determine the number of moles of KIO₃ present in the solution.

From the given information,

Mass of KIO₃ = 562 g

Using the formula

[tex]Number\ of\ moles = \frac{Mass}{Molar\ mass}[/tex]

Molar of KIO₃ = 214.001 g/mol

∴ Number of moles of KIO₃ present = [tex]\frac{562}{214.001}[/tex]

Number of moles of KIO₃ present = 2.62615595 moles

Now, for the molarity (that is, concentration) of the KIO₃ solution,

Using the formula,

[tex]Concentration = \frac{Number\ of\ moles}{Volume}[/tex]

From the question,

Volume of the solution = 4.30 L

∴ Concentration of the KIO₃ solution = [tex]\frac{2.62615595}{4.30}[/tex]

Concentration of the KIO₃ solution = 0.610734 M

Concentration of the KIO₃ solution ≅ 0.611 M

Hence, the molarity of the KIO₃ solution is 0.611 M

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