A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 205.6-cm and a standard deviation of 1.1-cm. For shipment, 10 steel rods are bundled together. Find P25, which is the average length separating the smallest 25% bundles from the largest 75% bundles. P25

Respuesta :

Answer:

P25 = 205.365cm

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

In this problem, we have that:

[tex]\mu = 205.6, \sigma = 1.1, n = 10, s = \frac{1.1}{\sqrt{10}} = 0.34785[/tex]

Find P25, which is the average length separating the smallest 25% bundles from the largest 75% bundles. P25

This is the value of X when Z has a pvalue of 0.25. So X when Z = -0.675.

So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]-0.675 = \frac{X - 205.6}{0.34785}[/tex]

[tex]X - 205.6 = -0.675*0.34785[/tex]

[tex]X = 205.365[/tex]

P25 = 205.365cm