Answer:
The resistance is found to be 6Ω
The current is found to be 0.66 A
Explanation:
The resistance of a conductor in terms of its dimensions is given as:
R = ρL/A
where,
R = resistance = ?
ρ = resistivity = 3 x 10⁴ Ω.m
L = Length = 4 mm = 0.004 m
A = Cross-sectional area = 0.2 mm² = 0.2 x 10⁻⁶ m²
Therefore,
R = (3 x 10⁴ Ω.m)(0.004 m)/(0.2 x 10⁻⁶ m²)
R = 6 Ω
Now, the potential difference between both ends of the resistor is:
ΔV = 16 V - 12 V = 4 V
Now, from Ohm's Law:
V = IR
I = V/R
I = 4 V/ 6 Ω
I = 0.66 A
