Answer:
116.43 kJ of heat is released when 100.0 g of calcium oxide reacts with excess water.
Explanation:
[tex]CaO (s) + H_2O (l)\rightarrow Ca(OH)_2 (s)[/tex] , ΔH = -65.2 kJ
Mass of calcium oxide = 100.0 g
Moles of calcium oxide = [tex]\frac{100.0 g}{56 g/mol}=1.7857 mol[/tex]
According to reaction, 1 mole of calcium oxide on reaction with water gives off 65.2 kilo Joules of heat. Then 1.7857 moles of calcium oxide will give:
[tex]\frac{65.2}{1}\times 1.7857 kJ=116.43 kJ[/tex]
116.43 kJ of heat is released when 100.0 g of calcium oxide reacts with excess water.