The slope of the line is [tex]m=-\frac{1}{2}[/tex]
Explanation:
Given that a coordinate plane with a straight line passing through the points [tex](-4,2)[/tex] , [tex](0,0)[/tex] and [tex](4,-2)[/tex]
We need to determine the slope of the line.
The slope of the line can be determined using the formula,
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Since, the points [tex](-4,2)[/tex] , [tex](0,0)[/tex] and [tex](4,-2)[/tex] lie on the straight line and the slope of all the points in a straight line have the same slope.
Hence, let us consider the points [tex](-4,2)[/tex] and [tex](0,0)[/tex]
Let us substitute these points in the slope formula, we have,
[tex]m=\frac{0-2}{0+4}[/tex]
Simplifying, we get,
[tex]m=\frac{-2}{4}[/tex]
Dividing, we get,
[tex]m=-\frac{1}{2}[/tex]
Hence, the slope of the line is [tex]m=-\frac{1}{2}[/tex]
