An 80-percent-efficient pump with a power input of 20 hp is pumping water from a lake to a nearby pool at a rate of 1.5 ft3/s through a constant-diameter pipe. The free surface of the pool is 80 ft above that of the lake. Determine the mechanical power used to overcome frictional effects in piping.

Respuesta :

Answer:

mechanical power used to overcome frictional effects in piping is 2.37 hp

Explanation:

given data

efficient pump = 80%

power input = 20 hp

rate = 1.5 ft³/s

free surface = 80 ft

solution

we use mechanical pumping power delivered to water is

[tex]{W_{u}}= \eta {W_{pump}}[/tex]  .............1

put here value

[tex]{W_{u}}[/tex]  = (0.80)(20)

[tex]{W_{u}}[/tex] = 16 hp

and

now we get change in the total mechanical energy of water is equal to the change in its potential energy

[tex]\Delta{E_{mech}} = {m} \Delta pe[/tex]   ..............2

[tex]\Delta {E_{mech}} = {m} g \Delta z[/tex]  

and that can be express as

[tex]\Delta {E_{mech}} = \rho Q g \Delta z[/tex]     ..................3

so

[tex]\Delta {E_{mech}} = (62.4lbm/ft^3)(1.5ft^3/s)(32.2ft/s^2)(80ft)[\frac{1lbf}{32.2lbm\cdot ft/s^2}][\frac{1hp}{550lbf \cdot ft/s}][/tex]      ......4

solve it we get

[tex]\Delta {E_{mech}} = 13.614[/tex] hp

so here

due to frictional effects, mechanical power lost in piping

we get here

[tex]{W_{frict}} = {W_{u}}-\Delta {E_{mech}}[/tex]  

put here value

[tex]{W_{frict}}[/tex] = 16 -13.614

[tex]{W_{frict}}[/tex] = 2.37  hp

so mechanical power used to overcome frictional effects in piping is 2.37 hp