Explanation:
The given data is as follows.
Moles of propylene = 100 moles, [tex]T_{i}[/tex] = 300 K
[tex]T_{f}[/tex] = 800 K, [tex]V_{i} = 2 m^{3}[/tex]
[tex]V_{f} = 0.02 m^{3}[/tex], [tex]C_{p}[/tex] of propylene = 100 J/mol
Now, we assume the following assumptions:
Since, it is a compression process therefore, work will be done on the system. And, work done will be equal to the heat energy liberating without any friction.
W = [tex]mC_{p} \Delta T[/tex]
[tex]100 moles \times 100 J/mol K (800 - 300) K[/tex]
= [tex]5 \times 10^{6} J[/tex]
= 5 MJ
Thus, we can conclude that a minimum of 5 MJ work is required without any friction.
