In the following Lewis acid-base reaction, identify the compounds as acid, base, conjugate acid, and conjugate base. Zn(OH)3-(aq) + OH-(aq) ↔ Zn(OH)42-(aq) Zn(OH)3-(aq) Answer 1 OH- Answer 2 Zn(OH)42- Answer 3

Respuesta :

Answer:

Acid : [tex]Zn(OH)_3^{-}[/tex]

Conjugate base :  [tex]Zn(OH)_4^{2-}[/tex]

Base:  [tex]OH^-[/tex]

Explanation:

According to the Lewis concept :

  • An acid is defined as a substance that accepts electron pairs .
  • Base is defined as a substance which donates electron pairs.

According to the Bronsted-Lowry conjugate acid-base theory:

  • An acid is defined as a substance which looses donates protons and thus forming conjugate base .
  • A base is defined as a substance which accepts protons and thus forming conjugate acid.

Given reaction :

[tex]Zn(OH)_3^{-}(aq) + OH^-(aq)\rightleftharpoons Zn(OH)_4^{2-}(aq)[/tex]

[tex]Zn(OH)_3^{-}[/tex] is acting as an acid because it is accepting hydroxide ion.And after accepting hydroxide ion it forms its conjugate base that is [tex]Zn(OH)_4^{2-}[/tex]

Since,[tex]Zn(OH)_3^{-}(aq)[/tex] is acting as an acid [tex]OH^-[/tex] will obviously act as base.