Answer:
1815 feet
Explanation:
According to the question,
[tex]s\propto t^2[/tex]
[tex]s = kt^2[/tex] (k is an arbitrary constant)
[tex]k = \dfrac{s}{t^2}[/tex]
[tex]\dfrac{s_1}{t_1^2} = \dfrac{s_2}{t_2^2}[/tex]
[tex]s_2 = s_1\left(\dfrac{t_2}{t_1}}\right)^2 = 960\times\left(\dfrac{11}{8}\right)^2 = 1815\text{ feet}[/tex]
