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A box is dropped onto a conveyor belt moving at 3.40 m/s. If the coefficient of friction between the box and the belt is 0.270, how long will it take before the box moves without slipping

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fahadkatsina

Answer:t=1.28 seconds

Explanation:

The newton law of motion said

Force= mass × acceleration

The friction force said

a= u . g

a = 0.270 × 9.81

a=2.65m/s^2

Now applied the kinematics equation

v= u+ at

v=3.40 and u= 0

Now

t= 3.40/2.65

t=1.28 seconds

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