Suppose that the value of a stock varies each day from $10.22 to $40.58 with a uniform distribution. Given that the stock is greater than $20, find the probability that the stock is more than $34. Give your answer accurate to four decimal places.

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Answer:

0.3197 = 31.97% probability that the stock is more than $34.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

[tex]P(X \leq x) = \frac{x - a}{b-a}[/tex]

For this problem, we have that:

Suppose that the value of a stock varies each day from $10.22 to $40.58 with a uniform distribution.

This means that [tex]a = 10.22, b = 40.58[/tex]

Given that the stock is greater than $20

This means that we can use [tex]a = 20[/tex]

Find the probability that the stock is more than $34.

Either the stock is 34 or less, or it is more than 34. The sum of the probabilities of these events is decimal 1. So

[tex]P(X \leq 34) + P(X > 34) = 1[/tex]

We want P(X > 34).

[tex]P(X > 34) = 1 - P(X \leq 34) = 1 - \frac{34 - 20}{40.58 - 20} = 0.3197[/tex]

0.3197 = 31.97% probability that the stock is more than $34.