Respuesta :
Answer:
Let X the random variable that represent the pulse rates of a population, and for this case we know the distribution for X is given by:
[tex]X \sim N(77.5,11.6)[/tex]
Where [tex]\mu=77.5[/tex] and [tex]\sigma=11.6[/tex]
For this case the z score given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
And for this case the z score is without units, so the correct answer would be:
The z scores are numbers without units of measurement.
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the pulse rates of a population, and for this case we know the distribution for X is given by:
[tex]X \sim N(77.5,11.6)[/tex]
Where [tex]\mu=77.5[/tex] and [tex]\sigma=11.6[/tex]
For this case the z score given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
And for this case the z score is without units, so the correct answer would be:
The z scores are numbers without units of measurement.
