A gas has a volume of 36.0 L and a pressure of 750. torr when the temperature is 10. °C. What is the pressure if the volume changes to 15.0 L and the temperature changes to 78 °C, if the amount of gas stays the same?

Respuesta :

Answer: 2232 torr

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas = 750 torr

[tex]P_2[/tex] = final pressure of gas = ?

[tex]V_1[/tex] = initial volume of gas = 36.0 L

[tex]V_2[/tex] = final volume of gas = 15.0 L

[tex]T_1[/tex] = initial temperature of gas = [tex]10^oC=273+10=283K[/tex]

[tex]T_2[/tex] = final temperature of gas = [tex]78^oC=273+78=351K[/tex]

Now put all the given values in the above equation, we get:

[tex]\frac{750\times 36}{283}=\frac{P_2\times 15.0}{351}[/tex]

[tex]P_2=2232torr[/tex]

The pressure  will be 2232 torr if the volume changes to 15.0 L and the temperature changes to 78 °C, if the amount of gas stays the same.