Answer:
Step-by-step explanation:
Given that a common inhabitant of human intestines is the bacterium Escherichia coli.
A cell of this bacterium in a nutrient-broth medium divides into two cells every 20 minutes.
Initial population = 71 cells
Doubles in 1/3 of an hour
[tex]P = P_o (2)^{t/3}[/tex], where t is the no of hours.
[tex]P = 71 (2)^{t/3}[/tex]
Rate of growth = derivative of P
= [tex]71(2)^{t/3} *(1/3)ln 2\\= \frac{71}{3} (2)^{t/3} ln 2[/tex]
