Answer:
0.02M is the total concentration of ions in the diluted solution
Explanation:
We can apply the formula for dilution, to determine the [NaCl]
2 mL . 0.05M = 10 mL . M
M = 2 mL . 0.05M / 10 mL → 0.01 M
In order to determine the [ions] we dissociate our solute:
NaCl → Na⁺ + Cl⁻
Our solute concentration in diluted solution is 0.01M and the ratio with the ions is 1:1, so the total concentration of ions in the diluted solution is:
[Na⁺] + [Cl⁻] = 0.01 + 0.01 = 0.02M
For x moles of NaCl, it corresponds x moles of Na cation and x moles of Cl anion.
The total concentration of ions in the diluted solution is 0.02 M.
Here we applied the dilution formula for measuring the [NaCl]
So,
2 mL. 0.05M = 10 mL . M
M = 2 mL . 0.05M / 10 mL
= 0.01 M
Now the balanced chemical equation should be
NaCl → Na⁺ + Cl⁻
here the total concentration of ions in the diluted solution is
[Na⁺] + [Cl⁻]
= 0.01 + 0.01
= 0.02M
Hence, The total concentration of ions in the diluted solution is 0.02 M.
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