Answer:
__[HF]²__
[H2][F2]
Explanation:
Kc works with the molar concentrations in equilibrium and the expression for Kc, for this general reaction is:
2A(g) + 3B (g) ⇄ 4C(g) + 5D(g)
Kc = [C]⁴ . [D]⁵ / [B]³ . [A]²
The reaction is: H₂ (g) + F₂ (g) ⇌ 2HF(g)
Expression for Kc in this reaction is: [HF]² / [H₂] . [F₂]
The equilibrium constant of a chemical reaction is the value of its reaction quotient at chemical equilibrium, a state approached by a dynamic chemical system after sufficient time has elapsed at which its composition has no measurable tendency towards further change.
The equilibrium depends on the following:-
Kc works with the molar concentrations in equilibrium and the expression for Kc, for this general reaction is:
[tex]2A(g) + 3B (g)---> 4C(g) + 5D(g)\\\\Kc = \frac{[C]^4 * [D]^5}{[B]^3 * [A]^2}\\\\The reaction is: H_2 (g) + F_2 (g) ---> 2HF(g)[/tex]
Expression for Kc in this reaction is: [tex]=\frac{[HF]^2}{ [H_2] * [F_2]}[/tex]
Hence, the correct option is:-
[tex][HF]^2\\ [H2][F2][/tex]
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https://brainly.com/question/19912864
