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Alexandra is attempting to drag her 32.6 kg golden retriever across the wooden floor by applying a horizontal force. What force must she apply to move the dog with a constant speed of 0.95 m/s? The coefficient of friction between the dog and the floor is 0.72

Respuesta :

opudodennis

Answer:

230.26 N

Explanation:

Since the speed is constant, acceleration is zero hence the net force will be given by the product of mass, coefficient of friction and acceleration due to gravity

F=0.72*32.6*9.81=230.26 N

Cricetus

The force applied by Alexandra will be "230 N".

Given values:

  • Coefficient of friction, [tex]\mu = 0.72[/tex]
  • Constant speed, [tex]v = 0.95 \ m/s[/tex]
  • Mass, [tex]m = 32.6 \ kg[/tex]

The net force will be:

→ [tex]F_{net} = F-\mu mg[/tex]

Since acceleration,

a = 0

           

hence,

The force applied by her will be:

→ [tex]F = \mu mg[/tex]

By putting the values, we get

→     [tex]= 0.72\times 32.6\times 9.8[/tex]

      [tex]= 230 \ N[/tex]

Thus the above answer is right.

Learn more about speed here:

https://brainly.com/question/20330326

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