Answer:
The answer to your question is V2 = 3.7 L
Explanation:
Data
Volume 1 = 3.5 L
Temperature 1 = 25°C
Temperature 2 = 40°C
Pressure = cte.
Volume 2 = ?
Formula
To solve this problem use the Charles' law
V1/T1 = V2/T2
- Solve for V2
V2 = V1T2 / T1
- Convert temperature to °K
Temperature 1 = 25 + 273 = 298°K
Temperature 2 = 40 + 273 = 313°K
- Substitution
V2 = (3.5)(313) / 298
- Simplification
V2 = 1095.5 / 298
- Result
V2 = 3.7 L
Answer:
The new volume of the balloon is 3.68 L
Explanation:
Step 1: Data given
The initial volume of the balloon = 3.50 L
The temperature = 25.0 °C = 298 K
The temperature changes to 40.0 °C = 313 K
The pressure remains constant at 1.0 atm
Step 2: Calculate the new volume of the balloon
V1/T1 = V2/T2
⇒with V1 = the initial volume of the balloon = 3.50 L
⇒with T1 = the initial temperature = 298 K
⇒with V2 = the new volume = TO BE DETERMINED
⇒with T2 = the new temperature = 313 K
3.50 L / 298 K = V2 / 313 K
V2 = 3.68 L
The new volume of the balloon is 3.68 L
