Answer: 143.66 grams of M (g) is contained in 396 g of the mineral
Explanation:
Given : mineral contains metal M and sulphur
Mass of mineral = 4.3 g
Mass of metal M in mineral = 1.56 g
Thus if 4.3 gram of mineral contains metal = 1.56 g
Using unitary method for solving this :
1 g of mineral contains metal =[tex]\frac{1.56}{4.3}\times 1=0.36[/tex]
396 g of mineral contains metal =[tex]0.36\times 396=143.66 g[/tex]
Thus 143.66 grams of M (g) is contained in 396 g of the mineral