Answer:
The answer to your question is Kc = 260.86
Explanation:
Balanced chemical reaction
CO + 3H₂ ⇔ CH₄ + H₂O
Process
1.- Write the equilibrium constant for the reaction
Kc = [tex]\frac{[CH_{4}][H_{2}O]}{[CO][H_{2}]^{3}}[/tex]
2.- Substitute values in the formula
Kc = [tex]\frac{[1.8][2]}{[0.51][0.3]^{3}}[/tex]
3.- Simplification
Kc = [tex]\frac{3.6}{0.0138}[/tex]
4.- Result
Kc = 260.86
Answer:
The equilibrium constant for this reaction is 261.4
Explanation:
Step 1: Data given
The equilibrium mixture contains:
0.51M CO
0.30M H2
1.8M CH4
2.0 M H2O
Step 2: The balanced equation
CO(g) + 3H2 (g) ⇌ CH4 (g) + H2O (g)
For 1 mol CO we need 3 moles H2 to produce 1 mol CH4 and 1 mol H2O
Step 3: Calculate Kc
Kc = [CH4]*[H2O] / [CO]*[H2]³
⇒with [CH4] = 1.8 M
⇒with [H2] = 0.30 M
⇒with [H2O] = 2.0 M
⇒with [CO] = 0.51 M
Kc = (1.8*2.0) / (0.51*0.30³)
Kc = 261.4
The equilibrium constant for this reaction is 261.4
