The solutions of the equation are [tex]x=-2[/tex] and [tex]x=-8[/tex]
Explanation:
Given that the equation is [tex]x^{2} +10x+16=0[/tex]
We need to determine the solutions of the equation.
The solution can be determined by factoring the equation.
Thus, we have,
[tex]x^{2} +10x+16=0[/tex]
[tex](x+2)(x+8)=0[/tex]
Simplifying, we get,
[tex]x=-2[/tex] and [tex]x=-8[/tex]
Thus, the solutions of the equation are [tex]x=-2[/tex] and [tex]x=-8[/tex]
Now, we shall write the equation in standard form.
The equation in standard form is given by
[tex]ax^{2} +bx+c=0[/tex]
Hence, the equation [tex]x^{2} +10x+16=0[/tex] is in standard form.
