Answer:
0.634 is the required probability.
Step-by-step explanation:
We are given the following in the question:
Total number of students = 30
Number of girls = 17
[tex]n(G) =17[/tex]
Number of boys = 13
[tex]n(B) = 13[/tex]
Number of A students = 5
[tex]n(A) = 5[/tex]
Number of A students that are girl = 3
[tex]n(A\cap G) = 3[/tex]
We have to find the probability choosing a girl or an A student.
We evaluate:
[tex]n(A\cup G) = n(A) + n(G) - n(A\cap G) = 5 + 17-3 = 19[/tex]
[tex]\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}[/tex]
[tex]P(A\cup G) = \dfrac{n(A\cup G) }{30} = \dfrac{19}{30} = 0.634[/tex]
0.634 is the probability of choosing a girl or an A student.
