Answer:
[tex]a=3x, b=7[/tex]
Step-by-step explanation:
The given polynomial is [tex]9x^2-49[/tex]
We rewrite the polynomial as a difference f two squares.
[tex]9x^2-49=(3x)^2-7^2[/tex]
We need to compare this to the difference of squares identity:
[tex](a^2-b^2)=(a+b)(a-b)[/tex]
Putting a=3x and b=7, we have :
[tex](3x)^2-7^2=(3x+7)(3x-7)[/tex]
Therefore [tex]a=3x, b=7[/tex]