taterbuglee2003
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A single loop of wire with an area of 0.0800 m^2 is placed in a uniform magnetic field that has an initial value of 1.50 T. The field is perpendicular to the plane of the loop, and its strength is decreasing at a constant rate of 0.400 T/s. The loop has a resistance of 0.400. What current is induced in this loop?

Respuesta :

opudodennis

Answer:

0.0800A

Explanation:

Given the Area as [tex]A=0.0800m^2[/tex] and that the wire is perpendicularly placed in a magnetic field that has an initial value [tex]B=1.50T[/tex] and a decreasing constant [tex]|dB/dt|=0.400T/s[/tex], the magnitude of the induce emf is :

[tex]|\varepsilon|=|{\frac{d\Phi_B}{dt}}| \ \ \ \Phi_B=BAcos(\phi), \phi=0[/tex]

[tex]|\varepsilon|=A\frac{dB}{dt}\\\\|\varepsilon|=(0.0800m^2)(0.400T/s)=0.0320V[/tex]

To find the current induced in the loop of resistance 0.400 ohms:

[tex]I=\frac{\varepsilon}{R}\\\\=0.0320V/0.400\Omega\\\\I=0.0800A[/tex]

The induced current in the loop is 0.0800A

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