Respuesta :
Answer:
The equilibrium concentration of N2 is 2.22765 M
Explanation:
The air pollutant NO is produced in automobile engines from the high-temperature reaction:
N2(g)+O2(g) <--> 2NO(g) Kc=1.7 * 10^-3
Part A: Calculate the equilibrium concentration of N2 if the initial concentrations are 2.25 M N2 and 0.55 M O2. (This N2/O2 concentration ratio is the ratio found in air.)
Step 1: Data given
Initial concentration of N2 = 2.25 M
Initial concentration of O2 = 0.55M
Kc = 1.7 * 10^-3
Step 2: The initial concentrations
[N2] = 2.25 M
[O2] = 0.55 M
[NO] = 0M
Step 3: The concentrations at equilibrium
[N2] = 2.25 - x M
[O2] = 0.55 - x M
[NO] = 2x M
Step 4: Kc
Kc = 1.7 *10^-3 = (2x)² / (2.25 -x)(0.55 -x )
1.7 * 10^-3 = 4x² / (1.2375 - 2.80x +x² )
0.0017x² - 0.00476x + 0.002104 = 4x²
3.9983x² + 0.00476x - 0.002104 = 0
x = 0.02235
[N2] = 2.25 - x M = 2.25 - 0.02235 = 2.22765 M
[O2] = 0.55 - x M = 0.55 - 0.02235 = 0.52765 M
[NO] = 2x M = 2* 0.02235 = 0.0447 M
The equilibrium concentration of N2 is 2.22765 M
