Respuesta :
Answer:
[tex]-16t^2 + 1000>300[/tex]
[tex]t\in (9.01,\infty)[/tex]
Step-by-step explanation:
We are given the following in the question:
[tex]d = -16t^2 + 1000[/tex]
where d is the distance of an object above the ground and t is in seconds.
We have to find the time interval such that distance is greater than 300 feet above the ground.
[tex]d > 300\\d = -16t^2 + 1000>300\\-16t^2>-1300\\t^2 > 81.25\\t > \sqrt{81.25}\\t > 9.013\\\Rightarrow t\in (9.01,\infty)[/tex]
is the required time interval.
