Answer:
Mass = 24.4 g
Explanation:
Given data:
Mass of lithium nitride needed = ?
Volume of ammonia = 15.0 L
Solution:
Chemical equation:
Li₃N + 3H₂O → NH₃ + 3LiOH
One mole = 22.414 L
We will compare the volume of lithium nitride and ammonia.
NH₃ : Li₃N
22.414 : 22.414
15.0 : 15.0
Number of moles of lithium nitride:
PV = nRT
n = 1 atm ×15 L / 0.0821 atm.L / mol.K × 273 K
n = 15 /22.41 /mol
n =0.7
Mass of Lithium nitride:
Mass = number of moles × molar mass
Mass = 0.7 mol × 34.83 g/mol
Mass = 24.4 g
