Respuesta :
Answer: Volume of the air in the balloon after it is heated is [tex]1.68\times 10^6L[/tex]
Explanation:
To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1\text{ and }T_1[/tex] are the initial volume and temperature of the gas.
[tex]V_2\text{ and }T_2[/tex] are the final volume and temperature of the gas.
We are given:
[tex]V_1=1.27\times 10^6\\T_1=11^oC=(11+273)K=284K\\V_2=?\\T_2=103^oC=(103+273)K=376K[/tex]
Putting values in above equation, we get:
[tex]\frac{1.27\times 10^6}{284K}=\frac{V_2}{376}\\\\V_2=1.68\times 10^6L[/tex]
Thus volume of the air in the balloon after it is heated is [tex]1.68\times 10^6L[/tex]
