Answer:
[tex]\large\boxed{\large\boxed{820liter}}[/tex]
Explanation:
Use the ideal gas equation:
[tex]pV=nRT[/tex]
Where:
- p is the pressure: 202.6kPa
- n is the number of moles: 0.050 mol
- T is the temperatue in absolute scale: 400K
- R is the universal constant for ideal gases: 8.314 L-kPa / K-mol
- V is the volume
Substitute and solve for V:
[tex]202.6kPa\times V=0.050mol\times 8.314L\cdot kPa/k\cdot mol\times 400K\\ \\ \\ V=0.8207m^3[/tex]
Convert to liters:
[tex]V=0.8207m^3\times 1,000liter/m^3=820liters[/tex]
The answer is rounded to two significant figures.
