How many grams of hydrogen gas would be produced from the use of 9.5 miles of aluminum?
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Answer:
28.5g of H2
Explanation:
First, let us write a balanced equation for the reaction. This is illustrated below:
2Al + 6HCl —> 2AlCl3 + 3H2
From the balanced equation,
2moles of Al produced 3moles of H2.
Therefore, 9.5 moles of Al will produce = (9.5x3)/2 = 14.25moles of H2.
Now let us convert 14.25moles of H2 to grams as illustrated below:
Molar Mass of H2 = 2x1 = 2g/mol
Number of mole H2 = 14.25moles
Mass of H2 =?
Number of mole = Mass /Molar Mass
Mass = number of mole x molar Mass
Mass of H2 = 14.25 x 2
Mass of H2 = 28.5g