Respuesta :
Answer:
Magnetic field required for the given induced EMF is 1.41 T
Explanation:
Potential difference across the blood vessel is given as
[tex]E = vBd[/tex]
here we know that the speed is given as
[tex]v = 14.8 cm/s[/tex]
[tex]d = 4.80 mm[/tex]
[tex]E = 1 mV[/tex]
now we have
[tex]1 \times 10^{-3} = (14.8 \times 10^{-2})B(4.80 \times 10^{-3})[/tex]
[tex]B = 1.41 T[/tex]
Now volume flow rate of the blood is given as
[tex]Q = Av[/tex]
[tex]Q = \frac{\pi d^2v}{4}[/tex]
from above equation we have
[tex]v = \frac{E}{Bd}[/tex]
Now we have
[tex]Q = \frac{\pi d^2\frac{E}{Bd}}{4}[/tex]
[tex]Q = \frac{\pi E d}{4B}[/tex]
"1.41 T" would be the required magnetic field.
According to the question,
Speed,
- v = 14.8 mm
Diameter,
- d = 4.80 mm
Potential difference,
- E = 1 mV
Potential difference across the blood vessel will be:
→ [tex]E = vBd[/tex]
By substituting the values, we get
→ [tex]1\times 10^{-3} = (14.8\times 10^{-2})B (4.80\times 10^{-3})[/tex]
→ [tex]B = 1.41 \ T[/tex]
Now,
The volume flow rate will be:
→ [tex]Q = Av= \frac{\pi d^2 v}{4}[/tex]
from the above equation, we get
→ [tex]v = \frac{E}{Bd}[/tex]
then
→ [tex]Q = \frac{\pi d^2\frac{E}{Bd} }{4}[/tex]
[tex]= \frac{\pi Ed}{4B}[/tex]
Thus the above approach is right.
Learn more:
https://brainly.com/question/14848188