Answer:
Step-by-step explanation:
Given that a hypothesis test (right tailed) was conducted for comparing sample mean with population mean.
[tex]H0: \bar x = 12.6\\HA: \bar x > 12.6[/tex]
Sample size n = 25
Population std dev = [tex]\sigma = 3.2[/tex]
Std error of sample mean = sigma/sqrt n = 3.2/5 = 0.64
Sample mean = 13.4
Mean difference = 13.4-12.6 = 0.80
since population std deviation is known we can use Z test
Z= mean diff/std error = 1.25
a) p valu e= 0.10565
= 0.1057
b) Since p value is >0.10 accept H0.
C. Do not reject H0 since the p-value is greater than 0.10
c) If n =100, then we have std error of mean = 1/2 original = 0.32
Test statistic = 0.8/0.32 = 2.5
p value = 0.00621
d) Here since p <0.10, we reject null hypotehsis
B. Reject H0 since the p-value is smaller than 0.10