Respuesta :
Answer:
Explanation:
Work done = ∫Fdx
= ∫(cx-3.00x²) dx
[ c x² / 2 - 3 x³ / 3 ]₀²
= change in kinetic energy
= 11-20
= - 9 J
[ c x² / 2 - x³ ]₀² = - 9
c x 2² / 2 - 2³ = -9
2c - 8 = -9
2c = -1
c = - 1/2
Answer:
Explanation:
F = cx - 3x²
At x = 0 , Kinetic energy = 20 J
at x = 2 m, the kinetic energy = 11 J
Use work energy theorem
[tex]W = \int_{0}^{2}F(x) dx = \Delta K[/tex]
[tex]W = \int_{0}^{2}(cx-3x^{2}) dx = 11-20[/tex]
[tex]\frac{cx^{2}}{2}-x^{3}=-9[/tex]
2c - 8 = - 9
2c = - 1
c = - 0.5
