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Two equal point charges Q are separated by a distance d. One of the charges is released and moves away from the other due only to the electrical force between them. When the moving charge is a distance 3d from the other charge, what is its kinetic energy ?

Respuesta :

Answer:

kinetic energy of charge will be [tex](1/k)*(2Q^2/3d)[/tex]

Explanation:

First calculate the initial potential energy of each charge;

PE1=[tex](1/k)*(Q^2/d)[/tex];

When the charges are at distance of 3d then its potential energy is;

PE2=[tex](1/k)*(Q^2/3d)[/tex];

And kinetic energy is equal to difference between their potential energy at two different positions,

So,

K.E=PE1-PE2;

K.E=[tex](1/k)*(Q^2/d)-(1/k)*(Q^2/3d)[/tex];

K.E=[tex](1/k)*(2Q^2/3d)[/tex];

Hence the kinetic energy of charge will be [tex](1/k)*(2Q^2/3d)[/tex]

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