Respuesta :
Answer:
(a) The speed at first point is 8.33m/s.
(b) The acceleration of the antelope is 1.11m/s².
Explanation:
We have, from the kinematics equations, that:
[tex]a=\frac{v_2-v_1}{t} \\\\v_2^{2}=v_1^{2}+2ax[/tex]
Solving for the acceleration in the second equation, we have:
[tex]a=\frac{v_2-v_1}{t} \\\\a=\frac{v_2^{2} -v_1^{2} }{2x}[/tex]
Then, equating the two equations, we obtain:
[tex]\frac{v_2-v_1}{t}=\frac{v_2^{2} -v_1^{2} }{2x}\\\\\frac{2x}{t}=\frac{(v_2-v_1)(v_2+v_1)}{v_2-v_1}\\\\v_1=\frac{2x}{t}-v_2\\\\\implies v_1=\frac{2(70.0m)}{6.00s}-15.0m/s=8.33m/s[/tex]
So, the speed at the first point is 8.33m/s (a).
Next, we use the first equation to compute the acceleration:
[tex]a=\frac{15.0m/s-8.33m/s}{6.00s}=1.11m/s^{2}[/tex]
In words, the acceleration of the antelope is 1.11m/s² (b).
