Answer:
a) Q₂ = 150 cm³/s
b) Q₂ = 33.33 cm³/s
c) Q₂ =25.0 cm³/s
d) Q₂ = 0.01 cm³/s.
e) Q₂ = 0.03 cm³/s
Explanation:
a) Original flow rate, Q₁ = 100 cm³/s
Based on the Poiseulle's equation
ΔP = (128цLQ/πD⁴)
ΔP₂/ΔP₁ = 1.50
ΔP ∝ Q
ΔP₂/ΔP₁ = Q₂/Q₁
1.5 = Q₂/Q₁
Q₂ = 1.5 Q₁
Q₂ = 1.5 * 100
Q₂ = 150 cm³/s
b)ΔP = (128цLQ/πD⁴)
Q ∝1/ц
Q = k/ц
Q₁ = k/ц₁
Q₂ = k/ц₂
Q₂/Q₁ = ц₁/ц₂
ц₂/ц₁ = 3
ц₁/ц₂ =1/3
Q₂/100 = 1/3
Q₂ = 100/3
Q₂ = 33.33 cm³/s
c)Q ∝1/L
Q = k/L
Q₁ = k/L₁
Q₂ = k/L₂
Q₂/Q₁ = L₁/L₂
L₂/L₁ = 4
L₁/L₂ =1/4
Q₂/100 = 1/4
Q₂ = 100/4
Q₂ =25.0 cm³/s
d) Q ∝ D⁴
Q₂/Q₁ = (D₂/D₁)⁴
2R₂ = D₂
2R₁ = D₁
D₂/D₁ = R₂/R₁ = 0.1
Q₂/Q₁ = 0.1⁴
Q₂/Q₁ = 0.0001
Q₂ = 0.0001Q₁
Q₂ = 0.0001 * 100
Q₂ = 0.01 cm³/s.
e) Q ∝ D⁴∝ΔP∝1/L
Q = k D⁴ΔP/L
Q₂/Q₁ = (D₂/D₁)⁴(ΔP₂/ΔP₁)(L₁/L₂)
D₂/D₁ = R₂/R₁ = 0.1
L₂/L₁ = 1/2
L₁/L₂ = 2
ΔP₂/ΔP₁ = 1.5
Q₂/Q₁ = (0.1)⁴*(1.5)*(2)
Q₂/Q₁ = 0.0003
Q₂ = 0.0003 * 100
Q₂ = 0.03 cm³/s