The teacher asked 4 students to measure 4 different objects. The table shown represents their measurements. Which student had the largest percent error?
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Student 4 has the largest percent error.
Step-by-step explanation:
The percent error of a measurement is given by
[tex]p=\frac{|x-x_{true}|}{x_{true}}\cdot 100[/tex]
where
x is the value of the measurement
[tex]x_{true}[/tex] is the actual value
For student 1:
[tex]x=49\\x_{true}=50[/tex]
Percent error:
[tex]p=\frac{|49-50|}{50}\cdot 100=0.02\cdot 100=2\%[/tex]
For student 2:
[tex]x=25.5\\x_{true}=25[/tex]
Percent error:
[tex]p=\frac{|25.5-25|}{25.5}\cdot 100=0.0196\cdot 100 = 1.96\%[/tex]
For student 3:
[tex]x=7.5\\x_{true}=8[/tex]
Percent error:
[tex]p=\frac{|7.5-8|}{8}\cdot 100=0.0625\cdot 100 = 6.25\%[/tex]
For student 4:
[tex]x=2.1\\x_{true}=1.6[/tex]
Percent error:
[tex]p=\frac{|2.1-1.6|}{1.6}\cdot 100=0.3125\cdot 100 = 31.25\%[/tex]
So, student 4 has the largest percent error.
Learn more about errors:
brainly.com/question/2764830
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