Answer:
(0,-4)
Step-by-step explanation:
The complete question is
Quadrilateral JKLM was dilated according to the rule
DO,1/2 (x,y)( 1/2x1/2y) to create the image quadrilateral J'K'L'M', which is shown on the graph.
What are the coordinates of vertex J of the pre-image?
The picture in the attached figure
we know that
The rule of the dilation is
(x,y) -----> (1/2x,1/2y)
The coordinates of vertex J' are (0,-2) ----> see the graph
therefore
The x-coordinate of J (pre-image) multiplied by 1/2 must be equal to the x-coordinate of J' (image)
[tex]\frac{1}{2}x=0[/tex] -----> [tex]x=0[/tex]
The y-coordinate of J (pre-image) multiplied by 1/2 must be equal to the y-coordinate of J' (image)
[tex]\frac{1}{2}y=-2[/tex] -----> [tex]y=-4[/tex]
therefore
The coordinates of J are (0,-4)
