Answer:
[5(3a +b) - 4][ (3a +b) + 2]
Step-by-step explanation:
We can factorize the equation as follows:
5(3a + b)² +6 (3a +b) - 8 ..(1)
Let (3a +b) be y, therefore the question becomes
5y^2 + 6y - 8. .... (2)
Next, we have to multiply the first and last term together, and then find the factor such that the factors will result to 6. This is illustrated below:
5y^2 x - 8 = -40y^2
Factors of -40y^2 = 10y and - 4y
Substituting 10y and - 4y into the into equation (2) in place of 6y, we obtain:
5y^2 + 6y - 8
5y^2 + 10y - 4y - 8
Now, we factorize as follows:
5y(y + 2) - 4(y + 2)
Since we have same entity in both brackets, we shall pick one:
(5y - 4)(y + 2). .....(3)
But recall
y = (3a +b)
Substituting the value of y into equation (3), we have:
(5y - 4)(y + 2).
[ 5(3a +b) - 4 ][ (3a +b) + 2 ]
